WebDec 3, 2024 · DATE_SUB () function in MySQL is used to subtract a specified time or date interval to a specified date and then returns the date. Syntax : DATE_SUB (date, … WebI am trying to get the all records which are 2 hours or more old using this query: $minutes = 60 * 2 SELECT COUNT (id) AS TOTAL, job_id from tlb_stats WHERE log_time >= DATE_SUB (CURRENT_DATE, INTERVAL $minutes MINUTE) GROUP BY job_id It only selects the recent records and skips the old.
MySQL get the date n days ago as a timestamp - Stack Overflow
WebChange now () as per your requirement. select date_sub (str_to_date (concat (hour (now ()),':',floor (minute (now ())/5)*5),'%H:%i'),interval 5 minute) as start_time, str_to_date (concat (hour (now ()),':',floor (minute (now ())/5)*5),'%H:%i') as end_time, now (); Webpublic DateTime::sub ( DateInterval $interval ): DateTime Procedural style date_sub ( DateTime $object, DateInterval $interval ): DateTime Modifies the specified DateTime object, by subtracting the specified DateInterval object. Like DateTimeImmutable::sub () but works with DateTime . easy cornrows for beginners
SQL DATE_SUB() MySQL 減日期區間 - SQL 語法教學 Tutorial
Web10 What is your datatype for lastseen, Your query seems correct , just try with SELECT username, role, lastseen FROM database.accounts WHERE STR_TO_DATE (lastseen, '%Y-%m-%d %H:%i:%s') >= DATE_SUB (NOW (), INTERVAL 10 MINUTE) AND role='admin' Also make sure your PHP and MYSQL Server have same timezones Share … WebDATE if the date argument is a DATE value and your calculations involve only YEAR , MONTH, and DAY parts (that is, no time parts). ( MySQL 8.0.28 and later :) TIME if the … WebYou'll have to use DATE_ADD () and DATE_SUB () operators for dates. Take a look at the documentation: http://dev.mysql.com/doc/refman/5.5/en/date-and-time-functions.html Share Improve this answer Follow answered Sep 30, 2011 at 0:31 user684934 Add a comment 0 SELECT * FROM (`yourdb`) WHERE `timestamp` BETWEEN NOW () - INTERVAL 30 … easy corn pudding recipe with canned corn